Apple's iPhones are known for a bevy of features such as portrait mode in cameras, sleek and minimalist design and more, but it's seemingly late in adapting bigger sizes for its smartphones. Thus, the Cupertino-based smartphone maker is now planning to make it big, well, size wise.
According to a report, Apple may launch its biggest iPhone ever in 2020, a 6.7-inch model. That’s only about an inch less than the display of Apple’s iPad Mini, which measures 7.9 inches.
This development comes from a Korean news site, ETNews, which states that the three new models measuring 5.4-inch, 6.1-inch, and 6.7-inch, will be released in the fall of 2020. All the three models will come with OLED panels. The report also added that Apple may release a fourth model as an entry to 5G technology. The fourth model will therefore, support 5G network.
Currently, the biggest size of an iPhone model available is the iPhone 11 Pro Max which has a 6.5-inch display. The other models launched this September were the iPhone 11 and iPhone 11 Pro, which measure 5.94 inches and 5.67 inches, respectively.
Coming to the display models, according to the report, the Samsung Display will be the sole supplier of 5.4-inch and 6.7-inch OLED panels. This panel, which is called aY-OCTA' technology, is supplied to Samsung Electronics for its own smartphones. Specifically, it will supply on-cell touch flexible OLED panels.
However, in order to stabilize supply and demand, Apple has also chosen LG Display to be a supplier of 6.1-inch film touch method-based OLED panel, the report added.
Typically, the Cupertino-based company announces its new phones at and around the month of September every year in the Bay Area.